If a3 + b3 = 1344 and a + b = 28, then (a + b)2 – 3ab is equal t

a3 + b3 = [a + b] [a2 + b2 – ab]

(a + b)2 – 3ab = a2 + b2 + 2ab – 3ab

= a2 + b2 – ab

A.T.Q

1344 = 28[a2 + b2 – ab]

a2 + b2 – ab = 48

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